> For the complete documentation index, see [llms.txt](https://eaglepb2.gitbook.io/cpw/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://eaglepb2.gitbook.io/cpw/special/hong-kong-identity-card.md).

# Hong Kong Identity card

## Question

The Hong Kong Identity Card consists of 1 English letter and 6 numeric digits. A check digit, which could be 0 to 9 or A, is appended in brackets. It is calculated as follows:

* For letters, A is converted to value 1, B to value 2, and so on.
* For every HKID number $$LD\_1D\_2D\_3D\_4D\_5D\_6$$, the sum is $$S= 8L + 7D\_1 + 6D\_2 + 5D\_3 +4D\_4 + 3D\_5 +2D\_6$$.
* The check digit c shall be the smallest non-negative integer such that $$(s + c)%11=0$$. If c is 10, A is used instead.

Write a program to determine if the Identity Card is valid.

### Input Format

A line which consists of the format $$LD\_1D\_2D\_3D\_4D\_5D\_6(c)$$.

### Constraints

$$
A \le L \le Z
$$

$$
0 \le D\_1,D\_2,...D\_6\le9
$$

$$
0 \le c \le 9, or\ c=A
$$

### Output Format

Output 'YES' if the card is valid, otherwise, output 'NO'.

### Sample Inputs:

{% tabs %}
{% tab title="Input 0" %}

#### Input

```
A123456(3)
```

#### Output

```
True
```

{% endtab %}

{% tab title="Input 1" %}

#### Input

```
C876300(0)
```

#### Output

```
false
```

{% endtab %}
{% endtabs %}

<details>

<summary>Solution — Trivial</summary>

just follow the steps, and make it as a warmup. The harder part is actually how to split the characters instead.

Here's the solution:

```python
user_in = list(input())
user_in[0] = ord(user_in[0].upper()) - ord('A') + 1
if user_in[8] == 'A':
    user_in[8] = 10

big_num = 8
sum = 0

for ins in range(7):
    sum += big_num * int(user_in[ins])
    big_num -= 1

if((sum + int(user_in[8])) % 11 == 0):
    print("yes")
else:
    print("no")
```

</details>