Hong Kong Identity card

Difficulty: Basic

Question

The Hong Kong Identity Card consists of 1 English letter and 6 numeric digits. A check digit, which could be 0 to 9 or A, is appended in brackets. It is calculated as follows:

• For letters, A is converted to value 1, B to value 2, and so on.

• For every HKID number $LD_1D_2D_3D_4D_5D_6$, the sum is $S= 8L + 7D_1 + 6D_2 + 5D_3 +4D_4 + 3D_5 +2D_6$.

• The check digit c shall be the smallest non-negative integer such that $(s + c)\%11=0$. If c is 10, A is used instead.

Write a program to determine if the Identity Card is valid.

Input Format

A line which consists of the format $LD_1D_2D_3D_4D_5D_6(c)$.

Constraints

$$A \le L \le Z$$

$$0 \le D_1,D_2,...D_6\le9$$

$$0 \le c \le 9, or\ c=A$$

Output Format

Output 'YES' if the card is valid, otherwise, output 'NO'.

Sample Inputs:

Input 0

Input

A123456(3)

Output

True

Input 1

Input

C876300(0)

Output

false

Solution — Trivial

just follow the steps, and make it as a warmup. The harder part is actually how to split the characters instead.

Here's the solution:

user_in = list(input())
user_in[0] = ord(user_in[0].upper()) - ord('A') + 1
if user_in[8] == 'A':
    user_in[8] = 10

big_num = 8
sum = 0

for ins in range(7):
    sum += big_num * int(user_in[ins])
    big_num -= 1

if((sum + int(user_in[8])) % 11 == 0):
    print("yes")
else:
    print("no")